(10x^2+11x+7)/(2x+3)

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Solution for (10x^2+11x+7)/(2x+3) equation:


D( x )

2*x+3 = 0

2*x+3 = 0

2*x+3 = 0

2*x+3 = 0 // - 3

2*x = -3 // : 2

x = -3/2

x in (-oo:-3/2) U (-3/2:+oo)

(10*x^2+11*x+7)/(2*x+3) = 0

10*x^2+11*x+7 = 0

10*x^2+11*x+7 = 0

DELTA = 11^2-(4*7*10)

DELTA = -159

DELTA < 0

1 = 0

1/(2*x+3) = 0

x belongs to the empty set

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